In order to calculate the raw water requirement for a power plant, first of all we should know the losses in power plant.
As per new law raw water consumption should be 2.5 liters/kwh, presently it is around 4.5 liters/kwh.
Different losses in power plants :
A-Boiler
- Boiler blow down : 2% of steam generation
- Deaerator vent loss : 0.1% of Deaeration
- Soot blower steam : 0.8 to 1% of Boiler steam generation per day
B-Turbine & Process steam
- Process steam lines losses due to drain & traps : 1% of steam generation
- Cooling water evaporation loss : 2% of cooling water circulation
- Losses in process return condensate : 10% of steam given to process
C-Water treatment plant (WTP)
- Clarifier losses: 2% of total raw water input or 5% of DM water generation
- MGF back wash water loss : 40% of MGF inlet water (Back wash frequency : once in every 8 hours of operation)
- Reverse Osmosis (RO) plant reject water : 25% of total input water to RO plant or 35% of RO capacity
- Water losses in DM plant regeneration process : 30% of DM plant capacity for every regeneration process
- Losses due to leakages : 10 MT/day
- Water used for drinking & service : 10 MT/day
- Fire fighting system : 40 MT/day...Considered Jockey pump is running for 4 hours in a day at 10 M3/hr flow
- Blow down loss = 130 X 2% = 2.6 TPH
- Deaerator vent loss = 130 X 0.1% = 0.13 TPH
- Soot blower steam loss = 130 X 1% / 24 = 0.054 TPH
- Process steam loss = 130 X 1% = 1.3 TPH
- Losses in process steam condensate = 65 X 10% = 6.5 TPH
- SO total DM plant capacity = 2.6 + 0.13 + 0.054 + 1.3 + 6.5 =10.58 TPH
- DM plant is being stopped for 4 hours in a day for regeneration purpose,
- From the above example, quantity of steam going to the condenser is 130-65 = 65 TPH
- Cooling water circulation flow is = 65 X 60 = 3900 TPH
- Note: Considered 60 TPH of CW is required to condensate the 65 TPH of steam
- So total cooling tower loss = 3900 X 2% = 78 TPH
- Clarifier blow down losses = 12.96 X 5% = 0.65 TPH
- RO plant reject water = 12.96 X 35% = 4.53 TPH
- DM water regeneration losses (SAC+SBA+MB) = (3 X (12.96 X 30% ))/24 = 0.486 TPH
- Leakage losses = 10 TPD =10/24 =0.24 TPH
- Drinking & Service water = 10 TPD =10/24 = 0.24 TPH
- Fire fighting water = 10 TPD =10/24 =0.24 TPH
Thanks more adds boe and powerplant as a whole
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what is dm water requirement for 45 TPH Process boiler where 37 tph is going to process and no condensate return
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