Base | Representation |
---|---|

bin | 1100111100010111010110… |

… | …1100011110010010011111 |

3 | 1212101111012212212002001101 |

4 | 3033011311230132102133 |

5 | 3331131000004304234 |

6 | 50133420144053531 |

7 | 2666112301453333 |

oct | 317056554362237 |

9 | 55344185762041 |

10 | 14231201244319 |

11 | 4597467106514 |

12 | 171a1286042a7 |

13 | 7c2cc5476b67 |

14 | 372b1832d7c3 |

15 | 19a2bd680814 |

hex | cf175b1e49f |

14231201244319 has 2 divisors, whose sum is σ = 14231201244320. Its totient is φ = 14231201244318.

The previous prime is 14231201244287. The next prime is 14231201244329. The reversal of 14231201244319 is 91344210213241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14231201244319 - 2^{5} = 14231201244287 is a prime.

It is a super-2 number, since 2×14231201244319^{2} (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14231201244329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115600622159 + 7115600622160.

It is an arithmetic number, because the mean of its divisors is an integer number (7115600622160).

Almost surely, 2^{14231201244319} is an apocalyptic number.

14231201244319 is a deficient number, since it is larger than the sum of its proper divisors (1).

14231201244319 is an equidigital number, since it uses as much as digits as its factorization.

14231201244319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 37.

The spelling of 14231201244319 in words is "fourteen trillion, two hundred thirty-one billion, two hundred one million, two hundred forty-four thousand, three hundred nineteen".

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