Power plant and calculations

Tuesday, 27 May 2025

How to calculate the furnace temperature of a Boiler???

 

               How to calculate the furnace temperature of a Boiler???



The furnace temperature of a boiler depends on various factors such as fuel type, combustion efficiency, and heat transfer.

The total heat released by fuel during combustion is not completely utilized. Some heat is taken out by water vapour which is produced during combustion of hydrogen. Such heat value taken by considering heat taken away by water vapor is called NCV or LCV.


LCV = HCV – (9 X H2% X 586), Where H2 = Hydrogen% in fuel and 586 is latent heat of steam

Boiler furnace efficiency is a measure of how effectively the combustion process converts fuel energy into useful heat. It is typically calculated using the combustion efficiency method or the direct and indirect methods.

Example-1

A coal fired Boiler with lower calorific value 4200 kcal/kg is burnt in a Boiler with air fuel ration 6:1. Neglect the ash generated, calculate the maximum temperature attained in the furnace of the Boiler.

Assume the total heat generated by combustion of coal is given to the production of combustion. Consider the average specific heat of flue gas 0.24 kcal/kg & Boiler atmospheric temperature 30 deg C.

Given data;

L.C.V of fuel: 4200 kcal/kg

Specific heat of fuel: 0.24 kcal/kg

Boiler area temperature: 30 deg C

Furnace temperature = Heat released by combustion

No losses have been considered

Mg X Cpg X (t2-t1) = 1 X LCV

Mg X Cpg X (t2-t1) = 1 X 4200

Where, Mg = Mass of flue gas in kg

Cpg = Specific heat of flue gas

T2 = Maximum furnace temperature

(7+1) X 0.24 X (t2-30) = 4200

3.2 X t2 -57.6 = 4200

Furnace temperature t2 = 1330.5 deg C

Example-2:

A Biomass fired Boiler with GCV  2200 kcal/kg is burnt in a Boiler with air fuel ratio 3.5:1, Neglect the ash generated, calculate the maximum temperature attained in the furnace of the Boiler.

Assume the 70% of total heat generated by combustion of fuel is given to the products of combustion & 30% is losses. Consider the average specific heat of flue gas 0.24 kcal/kg & Boiler atmospheric temperature 32 deg C.

The details of the ultimate analysis of the fuel is;

Carbon, C: 23%

Oxygen, O2: 22%

Sulphur, S = 0%

Hydrogen, H2: 3.2%

Moisture, M: 50%

 

Given data;

GCV of the fuel: 2200 kcal/kg

LCV = HCV – (9 X H2% X 586), Where H2 = Hydrogen% in fuel and 586 is latent heat of steam

LCV = 2200-(9 X 3.2% X 586) = 2031.2 kcal/kg

Air to fuel ratio: 3.5:1

Combustion efficiency = 70%

Specific heat of flue gas, Cpg = 0.24 kcal/kg

Boiler area temperature t1 = 32 deg C

Therefore, we have;

Mg X Cpg X (t2-t1) = 1 X LCV

Where t2 = Furnace temperature to be attained

(3.5+1) X 0.24 X (t2-32) = 1 X 2031.2 X 70%

1.08 X t2 – 34.56 = 1421.84

Furnace temperature t2 = 1348.51 deg C

Example-3:

An oil-fired Boiler with a Lower calorific value (LCV) 10200 kcal/kg is burnt in a oil fired Boiler of capacity 100 TPH. The ratio of air fuel is 18:1, neglect the ash generation & heat loss in combustion, calculate the maximum temperature attained in the furnace of the Boiler.

Given data;

LCV of the fuel: 10200 kcal/kg

Air to fuel ratio: 18:1

Combustion efficiency :100

Specific heat of flue gas, Cpg = 0.24 kcal/kg

Boiler area temperature t1 = 30 deg C

Therefore, we have;

Mg X Cpg X (t2-t1) = 1 X LCV

Where t2 = Furnace temperature to be attained

(18+1) X 0.24 X (t2-30) = 1 X 10200

Furnace temperature, t2 =2266.84 deg C

 

Read more>>>>>100+ formulas for powerplant and calculation


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Friday, 21 March 2025

Top-14 reasons for Boiler Tubes failure

 

        What are the potential reasons for Boiler Tube failure??

Following are the direct causes for Boiler tubes or pressure parts failure.

1-Operation of the Boiler at higher pressure:

Boiler pressure parts are designed to operate at particular pressure for continuous operation. If they are being operated at higher pressure than recommended, leads to failure of pressure parts may be at welding joints or even at plain surfaces.

Boiler pressure parts lose their strength as they become older and older...

As per IBR-7, Boiler operating pressure should be reduced by 5% after 25 years of operation. That is A boiler operating at 109 kg/cm2 pressure should be operated at 103.55 kg/cm2 after 25 years.

Boiler operating pressure reduction chart

Age of the Boiler (From the date of first use in years

25

35

45

50

60

70

80

90

100

% of reduction in working pressure

5

10

15

20

30

40

50

60

70

 

2-Operation of the Boiler at higher temperature:

Operation of the Boilers at Higher temperatures can cause metallurgical weakening of the tubes, leading to deformation, cracking, or rupture. Continuous exposure to high temperatures causes creep, where the metal elongates and loses strength over time.

Rapid or excessive temperature variations cause thermal expansion and contraction, leading to cracks. Operation of the Boilers at higher temperature can also increase internal scaling.

3-Pressure parts or tubes internal scaling:













Read more>>>>>Boiler and Turbine hub

Poor quality of DM water can lead to internal scaling, this internal scaling of tubes results into poor heat transfer subsequently overheating and tube failure.

Calcium, Magnesium & silica present in water if not treated well can form hard scales on pressure parts internal surfaces.

Operation of the High Boiler at lower pH (< 8) for long time eventually leads filure of pressure parts.

In sugar-based cogeneration plants, there is the chance of entering sugar traces in process return condensate. Due to this, pH of feed water drops ( up to 6) quickly and result into tube failures.

Operation of the high-pressure Boiler at pH around 5 to 6 results into tubes failure in just 3 to 5 hours.


Thermal Camera E01 for Boiler internal inspection

4-Over heating of tubes:

Over heating of pressure parts due to wrongly set burners, air and internal scaling, poor water circulation & soot build up leads into tubes failure.

5-Erosion of tubes:






























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Erosion of pressure parts is mainly due to high flue gas velocity, bed materials in case of AFBC & CFBC boilers and even due to high velocity of steam and water.

So, ensuring right flue gas velocity at various locations of the Boiler is Vital to take care of erosion of pressure parts.

In case of AFBC & CFBC Boilers, bed coils (Evaporator & Super heaters) and water wall tubes erode due to bubbling beds.

Wrongly designed economiser, evaporators tubes and super heaters coils may suffer from erosion due to high velocity of water and steam. Usually, steam/ water velocity increases due to under sized tubes/coil or operation of the Boiler at over load.

Velocity of the fluid increases as the size of the tubes decreases.

Velocity (m/sec) = Flow (m3/sec) / Area (m2)

Based on above relation, velocity of the fluid increases as the Area of the tubes/pressure parts decreases and Flow increases.

Read>>>Boiler interview questions & Answers

6-Fatigue Failure:

Repeated thermal and mechanical stress due to frequent start up and shutdown cycles, frequent load variation leads to thermal shocks & failure of pressure parts.

7-Chemical cleaning of The Boilers internals:

Excessive use of chemicals especially acids during Boiler chemicals cleaning leads to Pressure parts failure during operation.

8-Stress & corrosion cracking:

Tubes fail due to corrosion, corrosion is mainly due to low pH, dissolved oxygen and other impurities in water which lead to pitting and weakening of the tubes. If Boilers are being operated in such conditions pressure parts go into failure.

9-Poor welding joints:

If welding joints quality is poor i.e if No standard welding procedure was followed during installation stages the joints fails upon small variation load or during abnormal operations.

Joints fail in following cases;

1-Poor welding techniques followed

Read>>>>> What is the significance of post weld and Pre-weld heat treatments (PWHTs)?

2-Poor skill of welder

3-Selecting wrong electrodes etc

4-Wet atmospheric condition

10-Poor operations:

What are the poor operation methods which lead to failure of pressure parts>>>>>??

Boiler pressure parts failure largely depends on Boiler operation skills of the operators.

Pressure parts may fail in following poor operation techniques

1-Not following Boiler start up procedures

2- Not following Boiler shut down procedures

3-Quick start-up of the Boiler, not following the Boiler start up curve

4-Not operating the vents & drains as per requirement or SOP

5-Sudden load variation

6-Operating the Boiler by ‘Bypassing the Boiler protections & Interlocks’.

7-Not providing minimum circulation steam to Boiler during start-ups, shut downs or even in case of ab normal operations.

Not knowing the function of ‘start up vent’ is the main reason for super heater coils failure during Boiler shut downs or low load operations.

Start up vent is used to provide minimum required flow to the Boilers during start-ups, which helps in cooling the super heater coils during No load operations

8-Operating the Boiler on low drum levels or not taking the quick shut downs if there is no water flow into the Boiler.

9-Wrong operation of attemperator. Sudden opening and closing of attemperator valves lead to thermal shocks in super heaters.

10-Operating the Boiler at higher drum levels. Operating the boiler at higher drum levels leads to carryover of wet steam or water into super heaters, which leads to thermal shock & tubes failure.

11-Giving water wall bottom headers blow down at high steam rate: This leads the starvation of water wall tubes.

12-Wrongly set safety valves & higher blow down percentage of safety valves:

In a Boiler, if drum safety valves pop up frequently before popping up of super heater safety valves, then it leads to the starvation of super heater coils and even failure.

12-Hydrogen damage:








Reaction between steel and water at high temperatures produces atomic hydrogen, which diffuses into the metal & leads to embrittlement and cracking, resulting in a fish mouth rupture.

13-Un even thermal expansion of pressure parts:

















Indian Boiler Regulations Book-

Un even of thermal expansion of Boiler tubes due to not following Boiler start up curves & start-up/Shut down procedures or restriction to thermal expansion lead to cracks or failure of joints of pressure parts.

 

Read>>>Why does the thermal expansion occur in Boilers??

14-Metallurgical defects:

Poor quality of metals used for manufacturing of Boiler pressure parts lead to failure of pressure parts during operation.

What are the main reasons for Boiler tubes ‘fish mouth’ opening??
























Fish mouth openings are catastrophic failures in Boilers, It’s a type of rupture where the tube bursts open, resembling a fish's mouth. This failure is highly dangerous and usually indicates severe operational or maintenance issues. The main reasons for a fish mouth opening in boiler tubes are:

Following are the major reasons for Boiler tubes ‘fish mouth’ opening.

1-Short term over heating: Occurs due to localized overheating when tubes are exposed to direct flame or high temperatures without sufficient cooling

2-Internal scaling

3-Operation of the Boiler with low water level

4-Starvation of super heater coils & water wall tubes

5-Hydrogen damage

6-Erosion of pressure parts, mostly in case of AFBC & CFBC Boilers.

7-Operation of the Boiler at higher pressure & Temperature than recommended.

8-Over heating.


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 Infrared Thermometer 

 Detects overheating tubes, hot spots, refractory failures, and abnormal furnace temperatures.

Sunday, 16 March 2025

How to calculate the specific fuel consumption of Power plant??





Specific Fuel Consumption (SFC) in Power Plants refers to the amount of fuel required to generate a unit of energy output. It is a key performance metric used to assess the efficiency of different power generation systems.

Specific fuel consumption (SFC)= Fuel consumption in kg/hr / Power generation in Kwh

Specific fuel consumption (SFC)= Specific steam consumption (SSC) / Steam to fuel ratio (SFR)

Factors affecting the Specific fuel consumption:

1-Steam consumption of the Turbine: Higher steam consumption of steam Turbine leads to more Specific fuel consumption (SFC).

2-Main steam parameters like pressure & temperature: Should be always on higher side but within design limit.

3-Boiler efficiency: High efficiency boilers consumer lesser fuel and hence Specific fuel consumption (SFC) will be on lower side.

4-Turbine efficiency: High efficiency Turbines will have higher out put on lesser input, hence Specific fuel consumption (SFC) of such Turbines is LESS

5-Fuel type & quality: High GCV fuel firing power plants will have lesser Specific fuel consumption (SFC).

6-Boiler operator competency: Efficient Operation of the Boiler, Turbine and other power plant equipment depends on the skill & competency of the operators.

7-Plant load factor: Operation of the Power plant units on higher loads or optimised loads leads to lower Specific fuel consumption (SFC) & Vice Versa, that is operation of plant on partial loads results into more fuel consumption and hence leads in more Specific fuel consumption (SFC).

8-Atmospheric conditions: Atmospheric conditions like temperature, pressure & humidity play a very vital role on achieving best efficiency of power plant equipment.

Specific fuel consumption (SFC) is also termed in terms of heat rate.

Heat rate = Energy consumed in kcal/ Power generation

It is measured in terms of kcal/kwh

Specific fuel consumption (SFC) is different for different fuels, fuels having higher heating value or calorific value will have lesser Specific fuel consumption (SFC) & fuels having lower calorific value will have higher specific fuel consumption.

It’s always recommended that Specific fuel consumption (SFC) should LESS.

Power plants having lesser Specific fuel consumption (SFC) are in more profit.

How to calculate the specific fuel consumption???

Specific steam consumption (SSC) is the amount of steam consumed by Turbine is always lesser to achieve lesser Specific fuel consumption (SFC). It’s measured in kg/kwh or MT/MW.

Similarly, Stam to fuel ratio (SFR) is the amount of steam generated on burning 1 MT or 1 Kg of fuel. It’s measured in kg/kg or MT/MT.

Examples:

1-Calculate the specific steam consumption of a 50 MW thermal power plant, which consumes around 960 MT of coal to generate 1200 MW power.

Given data,

Power generation = 1200 MW

Fuel consumed = 960 MT

Specific fuel consumption (SFC)= Fuel consumption in kg/hr / Power generation in Kwh

Specific fuel consumption (SFC)= 960/1200 =0.8 kg/kwh or 0.8 MT/MW

2-A 225 MW Thermal power plant’s steam turbines Specific steam consumption (SSC) is 3.5 MT/MW and it’s Boiler’s Steam to fuel ratio (SFR) is 4.5. Calculate the specific steam consumption of that plant

Given data,

Specific steam consumption (SSC) = 3.5

Stam to fuel ratio (SFR) = 4.5

Specific fuel consumption (SFC)= Specific steam consumption (SSC) / Steam to fuel ratio (SFR)

Specific fuel consumption (SFC)= 3.5/4.5 =0.78 Kg/kwh or 0.78 MT/MW
















Indian Boiler Regulations-2024 Publication



3-A Boiler consumes 25 MT of bio mass to generate 55 MT of steam per hour at pressure 67 kg/cm2 and temperature 490 deg C, which is used to run the 12 MW condensing Turbine. What would be the specific fuel consumption of this plant?

Read >>>>Why do high pressure Boilers have higher efficiency??

Given data,

Fuel consumption = 25 MT

Steam generated = 50 TPH

Power generation = 12 MW

Steam to fuel ratio (SFR) = Steam generated per hour / Fuel consumed per hour

Steam to fuel ratio (SFR) = 55 / 25 =2.2

Specific steam consumption (SSC) = Steam consumption by Turbine TPH / Power generated in MW

Specific steam consumption (SSC) = 50 / 12

Specific steam consumption (SSC) = 4.16 MT/MW

Specific fuel consumption (SFC)= Specific steam consumption (SSC) / Steam to fuel ratio (SFR)

Specific fuel consumption (SFC)= 4.16 / 2.2 =1.89 MT/MW


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